Question

logx+log(x+3)=1?

Answer 1

\[\log(x(x+3))=1\] by the property of the log that says
\[\log(a\times b)=\log(a)+\log(b)\]

Answer 2

then assuming this is base ten rewrite in equivalent exponential form
\[x(x+3)=10^1\]
\[x(x+3)=10\] by the the following
\[\log_b(x)=y\iff b^y=x\]

Answer 3

last job is to solve the quadratic equation
\[x(x+3)=10\]