Question

solve the equation by factoring
3x(x-4)=7x^2-13x

Answer 1

start with
\[3 x^2-12 x = 7 x^2-13 x\] then
\[x-4 x^2 = 0\]

Answer 2

or if you prefer
\[4x^2-x=0\]
\[x(4x-1)=0\]
\[x=0, x=\frac{1}{4}\]

Answer 3

How did you get that answer?