Question

Motion Problem

Answer 1

Gordon Rode His bike at 15 mph to get to his car. He then drove back at 45mph. If the entire trip took him 8 hours, how faraway was his car?

Answer 2

Probably messed up last time. Let's say x is the total distance.
x/15 + x/45 = 8
3x/45 + x/45 = 8
4x/45 = 8
x = 8x45/4=90 miles

Answer 3

These problems tend to be the same. First, remember
D= R*T (distance = rate (or speed) times time)
second, the distance going equals the distance coming back.

Now, some equations. time going plus time coming back = 8
T1 + T2= 8

using R*T, distance on the bike is 15*T1
distance in the care is 45*T2.
they are are equal, so

15*T1= 45*T2
T1+T2=8

now solve for T1 (or T2) and then find D