Circle P has a radius of 8 units with center P at (2, -1). Which equation defines circle P?
Answer

(x – 2)2 + (y + 1)2 = 64

(x + 2)2 + (y – 1)2 = 64

(x – 2)2 + (y + 1)2 = 8

(x + 2)2 + (y – 1)2 = 8

Question

Circle P has a radius of 8 units with center P at (2, -1). Which equation defines circle P?
Answer
		
(x – 2)2 + (y + 1)2 = 64
		
(x + 2)2 + (y – 1)2 = 64
		
(x – 2)2 + (y + 1)2 = 8
		
(x + 2)2 + (y – 1)2 = 8

anonymous · Answer

(x – 2)2 + (y + 1)2 = 64

anonymous · Answer

how did u fined that so i can do the next one by my self

myininaya · Answer

$$(x-h)^2+(y-k)^2=r^2 => (h,k)=center ; r=radius$$

anonymous · Answer

(x-a)^2 + (y-b)^2 = r^2 where (a,b) is center of circle and r = radius.

anonymous · Answer

The reason is as follows:
|dw:1330479636424:dw|