Question

There are 2 liquids, one 10%, one 20%. How much of each mixture would you mix to get 800mL of a 15% liquid?

Answer 1

x= amount of 10%
800-x= amount of 20%
.10x+.20(800-x)=.15(800)

Answer 2

so x=-11840

Answer 3

That cannot be.

Answer 4

\[.10x+160-.20x=120\]

Answer 5

\[-.10x=-40\]

Answer 6

\[x=400\]

Answer 7

i got 400 mL of 10% and 400 mL of 20%

Answer 8

Yep

Answer 9

ok