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Use the elimination method to solve the following system of equations. 2x – y + z = –3 2x + 2y + 3z = 2 3x – 3y – z = –4 Answer (–1, –3, –2) (1, 3, –2) (1, –3, –2) (1, 3, 2)
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ROW REDUCE THE FOLLOWING MATRIX \[\left( \matrix{2&-1&1&-3\\2&2&3&2\\3&-3&-1&-4} \right) \] \[\left( \matrix{1&0&0&1\\0&1&0&3\\0&0&1&-2} \right) \] you get x=1,y=3 and z=-2 or (1,3,-2)
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