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(3-2i)(4-7i)----this is imaginary numbers. can anyone solve
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FOIL, just remember that i^2=-1
right. my final answer is 26-29i. Nothing else to be done after that?
your final answer is wrong, try it again
But no, after you get a+bi, you can't factor any more
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(3-2i)(4-7i)= 12-21i-8i+14i^2= 12-29i+14i^2= 12-29i-14= -2-29i
thanks.
yw
howd you get from that first step to the second????? dockworker
using the foil method
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foil??
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