Question

Alright, this is an integration calculus problem, multiple choice. (Written out in the next post)

Answer 1

let K = \[\int\limits_{-2}^{3} \sin (x ^{1/3})\]
which of the following is then true?
1<k<or=2
2<k<or=3
3<k
0<k<1
k<or=0

Answer 2

I understand that since sin is an odd function, we can disregard the integral from -2 to 2, as it equals zero. but I don't understand what to do from there. it leaves me with:
\[\int\limits_{2}^{3} \sin x^{1/2}\]

Answer 3

sorry! in my last post I meant to write the integral of sin (x ^1/3), not x^1/2

Answer 4

How can you do the substitution if the derivative of x^1/3 isn't there?

Answer 5

yea i realized :(

Answer 6

oh :P