Question

The width of a rectangle is 18 in. less than its length. If the area of the rectangle is 1440 in^2, find the dimensions of the rectangle.

Answer 1

30in x 48in = 1440in^2

Answer 2

If l is the length, then the width is (l - 18)

Area of a rectangle = lw
A = l ((l - 18))
1440 = L^2 - 18L

L^2 - 18L = 1440

L^2 - 18L - 1440 = 0

(L - 48) (L + 30) = 0
L = 48 or L = -30

L = 48 and L - 18 = 30

48 by 30

Answer 3

additonal: we can't have -30 as the value for length for we're dealing with length and measure, there is no negative length in real application. .