I need help on dividing polynomials

Question

anonymous · Answer

14X+6X3$$14X+6X ^{3}-15-19X ^{2}\div3X ^{2}-2X+4$$

ash2326 · Answer

we have
$$\frac{(6x^3-19x^2+14x-15)}{3x^2-2x+4}$$
now we have
                     2x
                   -----------------------------------
 3x^2-2x+4 | 6x^3-19x^2+14x-15
                   -(  6x^3-4x^2+8x)
                        0-15x^2+6x-15

                     2x-5
                   -----------------------------------
 3x^2-2x+4 | 6x^3-19x^2+14x-15
                   -(  6x^3-4x^2+8x)
                    -15x^2+6x-15
                  -( -15x^2+10x-20)
                      0    -4x +5
so 2x-5 is the quotient and -4x+5 is the remainder

anonymous · Answer

thanks I still dont know how to do it

anonymous · Answer

so you just divide each one on the second line

anonymous · Answer

thank you!