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Mathematics 17 Online
OpenStudy (anonymous):

Identify the vertex and the y-intercept of the graph of the function y = 2(x + 1)2 + 4. Answer a. vertex: (1, 4) y-intercept: -6 b. vertex: (-1, -4) y-intercept: 4 c. vertex: (1, -4) y-intercept: -2 d. vertex: (-1, 4) y-intercept: 6

OpenStudy (amistre64):

y = a(x-Vx)^2 + Vy

OpenStudy (amistre64):

yint is the value at x=0

OpenStudy (anonymous):

i got B.

OpenStudy (amistre64):

b is wrong

OpenStudy (amistre64):

for simplicity: 2(1)^1 + 4 = 6

OpenStudy (anonymous):

For quadratic functions in the form \[y=a(x-h)^{2}+k\], the vertex is at (h,k).

OpenStudy (anonymous):

So A

OpenStudy (amistre64):

yint = 6; therefore theres only one option that fits

OpenStudy (anonymous):

Gotcha

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