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Identify the vertex and the y-intercept of the graph of the function y = 2(x + 1)2 + 4. Answer a. vertex: (1, 4) y-intercept: -6 b. vertex: (-1, -4) y-intercept: 4 c. vertex: (1, -4) y-intercept: -2 d. vertex: (-1, 4) y-intercept: 6
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y = a(x-Vx)^2 + Vy
yint is the value at x=0
i got B.
b is wrong
for simplicity: 2(1)^1 + 4 = 6
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For quadratic functions in the form \[y=a(x-h)^{2}+k\], the vertex is at (h,k).
So A
yint = 6; therefore theres only one option that fits
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