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OpenStudy (anonymous):
Find the exact solutions of the problem algebraically: (sin 2x + cos 2x)^2=1
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OpenStudy (anonymous):
(sin(2x) + cos(2x))² = 1 sin²(x) + 2sin(2x)cos(2x) + cos²(2x) = 1 2sin(2x)cos(2x) = 0 sin(4x) = 0 4x = nπ x = nπ/4
OpenStudy (anonymous):
underdtand?
OpenStudy (anonymous):
Thank you! I understand it now!
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