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Mathematics 22 Online
OpenStudy (anonymous):

Find the exact solutions of the problem algebraically: (sin 2x + cos 2x)^2=1

OpenStudy (anonymous):

(sin(2x) + cos(2x))² = 1 sin²(x) + 2sin(2x)cos(2x) + cos²(2x) = 1 2sin(2x)cos(2x) = 0 sin(4x) = 0 4x = nπ x = nπ/4

OpenStudy (anonymous):

underdtand?

OpenStudy (anonymous):

Thank you! I understand it now!

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