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Since I never got all of the final answers to my question the first time, I'll ask again. Simplify the expression and state the excluded values. <- (Answer both parts, please!) (z^2-4z-77)/(z^2-13z+22)
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factor both the numerator and denominator to get: (z-11)(z+4)/(z-11)(z-2) then you can cancel out the quantity (z-11) and therefore, the leftover quantities are: (z+4) and (z-2)
So is the answer (z+4)/(z-2)? Also, what are the excluded values?
(z+7)/(z-2)
(z) can never be 2 or else it will be undefined
@ jerwyn gayo: So they made a mistake? The answer is (z+7)/(z-2)?
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yeah. but' consider it as a simple mistake. .
OK, that's fine. Thank you.
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