A mass of 8.300 kg is suspended from a 1.670 m long string. It revolves in a horizontal circle.
The tangential speed of the mass is 2.637 m/s. Calculate the angle between the string and the vertical (in degrees).

Question

A mass of 8.300 kg is suspended from a 1.670 m long string. It revolves in a horizontal circle.
The tangential speed of the mass is 2.637 m/s. Calculate the angle between the string and the vertical (in degrees).

anonymous · Answer

$$T \cos \theta=Mg$$
$$T \sin  \theta=M \times(V ^{2} \div R)$$
$$\tan \theta=V ^{2} \div(R \times G)$$
$$\theta=22.6  degrees$$