Question

A mass of 8.300 kg is suspended from a 1.670 m long string. It revolves in a horizontal circle.
The tangential speed of the mass is 2.637 m/s. Calculate the angle between the string and the vertical (in degrees).

Answer 1

\[T \cos \theta=Mg\]
\[T \sin \theta=M \times(V ^{2} \div R)\]
\[\tan \theta=V ^{2} \div(R \times G)\]
\[\theta=22.6 degrees\]