Question

particle is projected from a point O on a horizontal plane with speed 35m/s at an angle of elevation α , where tan α =2. Find the maximum height above the plane of the particle and the equation of its trajectory.

Answer 1

for the equation of its trajectory.. can we use linear equation to solve?

Answer 2

quadratic is fine too

speed is meters so use gravity as -9.8

h(t)= -g/2 t^2 +Vsin(2)t

Answer 3

the vertex of this parabola is then:

Vsin(2)/g

Answer 4

so the question becomes; what is the height relative to? in this equation its relative to the starting height ... whatever that may be

Answer 5

thanks