Question

how do you find the vertex of the graph of the quadratic function of y=-2x^2-16x-20?
can someone explain it to me?

Answer 1

OK so you have the graph of a quadratic in the form of f(x)=ax^2+bx+c
The vertex (x,y) is located at
\[(\frac{-b}{2a},f(\frac{-b}{2a})\]

Answer 2

-b/2a

Answer 3

y=- 2x² -16x-20
= -2 ( x² + 8x + 10)
Vertex ( h, k)
h = -b/2a = -8/2 = -4
->k = f ( -4)
= -2 ( 16 -32 + 10 ) = 12
=> vertex ( -4, 12)