Solve for x:
http://i1225.photobucket.com/albums/ee397/motoshifter/125shifter%20-%20Open%20Study/2-29/2.png
Thanks
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OpenStudy (anonymous):
solve the qudratic
5x^2-20x-5=0
OpenStudy (anonymous):
x will have two solutions
OpenStudy (radar):
Were you able to get it to a quadratic form?
OpenStudy (anonymous):
5x^2-20x-5=0 is in the quadratic form,
I need to factor 20x?
OpenStudy (anonymous):
just divide through by 5,and then solve the qudratic
x^2-4x-1=0
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OpenStudy (anonymous):
ans==>x=2-root5
x=2+root5
OpenStudy (radar):
Take the left part (left of the equal sign) and add using the LCD of 5x
2x + 3 x+5
------- = ----- now cross multiply
5x 10
20x + 30 = 5x^2 +25x Consolidate
\[5x ^{2}+5x-30=0\] Divide thru by 5 getting
\[x ^{2}+x-6=0\]
Do you know how to solve the quadratic?
OpenStudy (radar):
Hint, it factors easily. Good luck
OpenStudy (anonymous):
sorry bro resolved the problem,turned out to be
5x^2+5x-30=0
then divide through by 5 to get it in radar's form....radar is right
OpenStudy (anonymous):
ans x=-3
x= 2
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