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Simplify this expression: 7x^2+35x+28/2x^2+13x+20
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21x^2+48x+20
7x^2+35x+28
If it's written like this 7x^2+35+28 _____________ < indicating division of the polynomials 2x^2+13x+20 then you have to factor both of them the top factors to (7x+7)(x+4) but from what I know the bottom one is unfactorable..
thanks
Sorry, the bottom one does factor I just had to try a little more :) (2x+5)(x+4)
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so your answer would be after cancelling (x+4) (7x+7) ______ (2x+5)
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