Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

[y=x^{2}-x+2 / \sqrt{x}\]

OpenStudy (anonymous):

y'=((2x-1)/sqrtx)-(x^2-x+2)*(1/2)*sqrtx

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

same quesiton but the equation is y=tan(x)/1+cos(x)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!