Question

The interior of a building is in the form of a cylinder of diameter 4.3 m and height 3.8 m, surmounted by a cone whose vertical angle is a right angle. Prove that the area of the surface is 71.83 m^2, and the volume of the building is 65.61 m^3.

Answer 1

I did in this way.
Surface area = CSA of cylinder + CSA of cone
Volume = Volume of cylinder + Volume of cone
But I am not getting the answer. Please help.

Answer 2

Bhai, did u get it?

Answer 3

Try this question.

Answer 4

http://www.meritnation.com/discuss/question/1808591/the-interior-of-a-building-is-in-the-form-of-a-cylinder-of-diameter-4-3m-and-height-3-8m-surmounted-by-a-cone-whose-vertical-angle-is-a-right-angl

Answer 5

problem solved...thanks....

Answer 6

Thnaks a lot.