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Mathematics 21 Online
OpenStudy (anonymous):

find the least number between 200 and 500 which leaves a remainder of 3 in each case when divided by 8,10,12 and 30

OpenStudy (anonymous):

answer is 243 !!! finally got it after 20 minutes !!!!!

OpenStudy (anonymous):

Least number above 200 which leaves 3 as remainder by the given numbers are - for 8 - 203 for 10 - 203 for 12 - 207 for 30 -213 and for the remainder to be 3 only they have to keepincreasing by the given number for example 213,243,273,303 all leave remainder 3 when divided by 30 and are increasing by 30 !!! so I found out that they all meet at 243 !!!!!

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