Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

Is anyone good at factoring?

OpenStudy (anonymous):

just ask,here are many people good at many things..

OpenStudy (anonymous):

\[2x^{3}+x^{2}+2x+1=0\]

OpenStudy (anonymous):

factor by grouping =x^2(2x+1)+(2x+1) =(2x+1)(x^2+1)

OpenStudy (anonymous):

thank you!

OpenStudy (anonymous):

yw

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!