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OpenStudy (anonymous):
Is anyone good at factoring?
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OpenStudy (anonymous):
just ask,here are many people good at many things..
OpenStudy (anonymous):
\[2x^{3}+x^{2}+2x+1=0\]
OpenStudy (anonymous):
factor by grouping =x^2(2x+1)+(2x+1) =(2x+1)(x^2+1)
OpenStudy (anonymous):
thank you!
OpenStudy (anonymous):
yw
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