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derivative of cos(2t) is?
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-2sin(2t)
t doesnt come out, huh. thanx!
would 3cos(2t) be 6cos(2t)?
i mean -6sin(2t)
the t DOES come out, but under disguise
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D[cos(2t)] = -cos(2t) * D[2t] D[cos(2t)] = -sin(2t) * 2 * D[t] D[cos(2t)] = -sin(2t) * 2 * 1
what about asin2t-bcos2t i got 2acos2t + 2bsin2t
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