find the equation of the line tangent to the curve y=cscx, at x= (pie)/4

Question

anonymous · Answer

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anonymous · Answer

how did u get to that?

anonymous · Answer

Click this http://www.wolframalpha.com/input/?i=find+the+equation+of+the+line+tangent+to+the+curve+y%3Dcscx%2C+at+x%3D+%28pie%29%2F4+find+the+equation+of+the+line+tangent+to+the+curve+y%3Dcscx%2C+at+x%3D+%28pie%29%2F4+

mikey · Answer

The derivative of cscx is -cscxcotx.  Plug in pi/4 and then you have the slope of the tangent line at the point of x=pi/4.  Then find the y value for x=pi/4 and you now have both a point and the slope.  The rest is just algebra.