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OpenStudy (anonymous):
find the equation of the line tangent to the curve y=cscx, at x= (pie)/4
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OpenStudy (anonymous):
OpenStudy (anonymous):
how did u get to that?
OpenStudy (anonymous):
OpenStudy (mikey):
The derivative of cscx is -cscxcotx. Plug in pi/4 and then you have the slope of the tangent line at the point of x=pi/4. Then find the y value for x=pi/4 and you now have both a point and the slope. The rest is just algebra.
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