Question

Let C be between D and E. Use the Segment Addition Postulate to solve for v.
DC=5v-12
CE=6v-10
DE=22

Answer 1

DE = DC + CE
22 = 5v-12 + 6v-10
11v = 22 + 22 = 44
=> v = 44/11 = 4

Answer 2

im confused on how you got 22 twice?

Answer 3

Given DE = 22 ( you posted )

Answer 4

no when you wrote 11v= 22 + 22=44.. how did you get the second 22?

Answer 5

-10 -12 = -22
Calculation ... v= ...+ 22

Answer 6

I dont understand if it equals to -22 how did it change to postive 22?