Question

One number exceeds another by 16. The sum of the number is 58. What are the numbers?

Answer 1

I set it up like this but I think its wrong x+16=58

Answer 2

There are two unknown numbers x and y. Since the sum is 58 then

x+y=58

one number is greater by 16 so that means
y = x+16
substitute y into the first equation

x+x+16=58
2x=42
x=21
y = 21+16
y=37

so your answer is 21 and 37

Answer 3

x + y = 58
x = y + 16

y = 58 - x
y = x - 16

y = y

58 - x = x - 16

x + x = 58 + 16
2x = 74
x = 74/2
x = 37
y = 21