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OpenStudy (anonymous):
Solve these proportions. x/3 = x + 2/2 x=
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sam (.sam.):
(x)/(3)=x+(2)/(2) x=3x+3 -2x=3 x=-(3)/(2)
sam (.sam.):
\[\huge OR\] (x)/(3)=(x+2)/(2) x=(3(x+2))/(2) 2x=(3(x+2))/(2)*2 2x=3(x+2) 2x=3x+6 -x=6 x=6*-1 x=-6
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