Question

what is the general solution of (x^2-3) dy/dx = xy

Answer 1

\[y = k \sqrt{x^{2}-3}\]

Answer 2

it can be written as 1/y dy=2x/2(x^2-3) dx
integrate on both side
ln(y)=lnsqrt(x^2-3)+lnc
y=Csqrt|(x^2-3)