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what is the equation for a line that passes through the points (3, -1) and (-6, 11)
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To find an equation for these two given points, we must first find teh slope using: y2-y1 ----- x2-x1 In this case: (3,-1) : (x1,y1) and (-6,11) : (x2,y2)
Solve the slope first for me, and then I can guide you through the rest.
12/-9
Which can simplify to?
4/-3
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Good work. Now, we must use the formula: (y-y1) = m (x-x1) 1) Pick any one of those two given points and substitute in for (x,y) 2) Use the 'm' or slope we just solved for, and plug it in. See what you get and you have your equation.
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