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OpenStudy (anonymous):
y=-16^2+64 quadratic equation how do I find the axis of symmetry and vertex help please >_<
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OpenStudy (anonymous):
|dw:1330668635725:dw|
hero (hero):
Use x = -b/(2a) to find axis of symmetry and x coordinate of vertex. Then substitute that x into the original equation to find the y coordinate of the vertex. Good luck.
hero (hero):
well, looks like x = 0
OpenStudy (anonymous):
|dw:1330668707274:dw|
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