Question

50= (2x)^2/(1-x)(2-x)/3..
what is the final ans.???

Answer 1

x=2.106942,0.9752496

Answer 2

Assuming this is your question:
\[\frac{\frac{(2x)^2}{(1-x)(2-x)}}{3}=50\]
\[\frac{4x^2}{(1-x)(2-x)}=150\]
\[4x^2=150(1-x)(2-x), x \neq 1, 2\]
\[4x^2=150(2-3x+x^2)\]
\[2x^2=75(x^2-3x+2)\]
\[2x^2=75x^2-225x+150\]
\[73x^2-225x+150=0\]
\[x=\frac{225 \pm \sqrt{225^2-4(73)(150)}}{2(73)}=\frac{225 \pm 5\sqrt{273}}{146}\]