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Solve the system: x^2+y^2=16 x+y=0
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\[(-2\sqrt{2},2\sqrt{2});(2\sqrt{2},-2\sqrt{2})\]
those pair of equations create the null sign... I approve.
thank you so much
picture: http://www3.wolframalpha.com/Calculate/MSP/MSP13771a0bh3ac1bchgf55000067g3c6hi9a5fcc4c?MSPStoreType=image/gif&s=15&w=400&h=298&cdf=RangeControl not that you need to graph it to solve it, but hey.
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