Question

Solve the system of equations involving two circles:
x^2+y^2+2x+2y=0
x^2+y^2+4x+6y+12=0

Answer 1

(-2,-2); (-6/5,-12/5)

you just need to set them equal to each other and solve for the variables.

Answer 2

(x+1)^2 + (y+1)^2 = 2

(x+2)^2 + (y+3)^2 = 1

Answer 3

(-2,-2); (-6/5,-12/5)