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OpenStudy (anonymous):
Solve the compound inequality 3x + 6 > 36 and 3x + 6 <= 54. Please show work? Thanks so much
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OpenStudy (hoblos):
3x + 6 > 36 3x > 30 x>10 3x + 6 <= 54 3x <= 48 x<= 16 10 < x <=16
OpenStudy (dape):
Solve them separately, and then combine the solutions: \[ 3x+6-6 > 36-6 \\ 3x > 30 \\ x > 10 \] and \[ 3x+6-6 <= 54-6 \\ 3x <= 48 \\ x <= 16 \] So \[ 10 < x <= 16 \] Or on interval form: \[ x=(10,16] \]
OpenStudy (hoblos):
@Luis Rivera it is opened at 10 **
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