Question

Solve the compound inequality 3x + 6 > 36 and 3x + 6 <= 54. Please show work? Thanks so much

Answer 1

3x + 6 > 36
3x > 30
x>10

3x + 6 <= 54
3x <= 48
x<= 16

10 < x <=16

Answer 2

Solve them separately, and then combine the solutions:
\[ 3x+6-6 > 36-6 \\
3x > 30 \\
x > 10 \]
and
\[ 3x+6-6 <= 54-6 \\
3x <= 48 \\
x <= 16 \]
So \[ 10 < x <= 16 \]
Or on interval form: \[ x=(10,16] \]

Answer 3

@Luis Rivera it is opened at 10 **