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Mathematics 13 Online
OpenStudy (anonymous):

What are the coordinates of the vertex of the graph of the function y = –x² + 6x –11?

OpenStudy (anonymous):

(3, –2) (3, 16) (–3, –29) (–3, –20)

OpenStudy (anonymous):

well i dont know for sure but here my opinion answer (-3,-29)

OpenStudy (anonymous):

im 50% sure

OpenStudy (anonymous):

dont take my word completely

OpenStudy (mani_jha):

Bring the right hand side to the form of a square(a^2 +2ab + b^2). For that you will need to multiply with equation with -1 to remove the - sign before x^2. Do that first, add 9 to both sides. Make it a square. The vertex of a parabola: \[(x-a)^{2}=k(y-b)\], is (a,b). Do, I need to show the steps?

OpenStudy (anonymous):

|dw:1330711564373:dw|the correct answer is 3,-2

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