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if xyz is not.. (picture below)
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3y^9z^3/4x^4
how did you get that? the part i dont get is when they say: not 0
They only say it is not 0 so you will know you are not dividing by 0 and can cancel out the common factors.
so does that mean i can plug in?
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\[\frac{6x^2y ^{12}z^6}{(2x^2yz)^3}=\frac{6x^2y ^{12}z^6}{8x^6y^3z^3}=\frac{3y^9z^3}{4x^4}\]
There are no values given to plug in.
This is just a problem where you simplify the fraction.
thanks ! i get it.
yw
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