Question

int i = 4;
int j = 6;
for(i=0; i<5;i++){
if(i>2){
System.out.println("i = "+ i);
for(j=j;j<10;j++){
System.out.println("j = "+ j);

}}
System.out.println("Enter a number for sum: ");

int cash= input.nextInt();
do{
int sum= cash +1;
System.out.println("the sum is: " + sum);

}while( cash<5);

}

}
}

Output
Enter a number for sum:
THIS IS MY OUTPUT AND I AM NOT SURE THAT WH

Answer 1

THIS IS MY OUTPUT AND I AM NOT SURE THAT WHY IS THE FIRST PART
i=0
...
j=6
....
not printed
Can any of you guys help me understand this and is there any good resource from where i would be able to get all this concepts.

Answer 2

It should skip printing the value of i when i=0, 1 and 2 since you have the if statement that requires i to be greater than 2.

Answer 3

First of all: What do want to achieve with this code snippet?

Answer 4

Maybe this will help:

//This does not make any sense at all, cause you
//re-init the 'i' with 0 in line 3 (for-loop)
int i = 4;

//This will make your second for-loop start at j=6
int j = 6;

//This will run for i=0 till i=4
for(i=0; i<5;i++)
{
//This will only be executed for i=3, i=4
if(i>2)
{
//Therefore this will print out:
// i=3
// i=4
System.out.println("i = "+ i);

//This loop will run for j=6 till j=9
for(j=j;j<10;j++)
{
//Therefor this will print out:
// j=6
// ...
// j=9
System.out.println("j = "+ j);
}
}

//This part will run 5 times (i=0 -> i=4)
System.out.println("Enter a number for sum: ");
int cash= input.nextInt();

//This loop only runs for inputs 0, 1, 2, 3, 4
//Output depends on the number you enter for cash
do
{
int sum= cash +1;
System.out.println("the sum is: " + sum);
}
while(cash<5);
}