Can someone check my answer? Perform the indicated operation and simplify. Come to the question so it can be displayed as an equation.
\[((x^2-10x+16)\div(x^2-1)) \times ((x-1) \div(1))\]
My answer: (x-8)(x-2)/(x+1)
No, its correct...
lol...thanks ^_^
-2 x -8 = 16 not 64 :P
woops ur right
;) those reading mistakes can be costly on tests, be careful. Good job greeneyes :)
I really don't like my teacher :L he gives us like 2 tests every week! Anyways, thanks :D
Too much tests are not nice. Well, tests are not nice in the first place...
They are stressful but sometimes helpful in the long run :p
Yeah, they help you learn and hone your skills ;)
Can someone check my answer for this one?\[((x^2+9x+20)/(x^2-11x+28)) \div ((x^2+8x+15)/(x^2-3x-4))\]
My answer: (x+4)(x+1)/(x-7)(x+3) Sorry these aren't clear :/
Yup, thats right =)
Thank you! This one seems easy but i got stuck...If you can, will you help me w/ this one? And i'm really sorry about these equations, i know they don't look good.\[((x^2+12x+36)/(x^2-8x+12)) \div((x^2-36)/(1))\]
My answer is probably wrong: (x+6)/(x-6)^2(x-2)
Its right :) Trust yourself, be more confident!
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