Question

hi need help in boolean algebra.
(A'+BC)(D'E+F)'+(D'E+F)
i know (D'E+F)'+(D'E+F)=1, but (A'+BC)(D'E+F)' should be done 1st,......

Answer 1

we have
\[(A'+BC)(D'E+F)'+(D'E+F)\]
we know that in Boolean Algebra
\[X+YZ=(X+Y)(X+Z)\]
we get
\[(D'E+F+(D'E+F)')(D'E+F+A'+BC)\]
so we get
\[(1)(D'E+F+A'+BC)\]
we get
\[D'E+F+A'+BC\]

Answer 2

ooh tyvm, do you mind if i ask another 1?

W'XY+WXZ+WY'Z+W'Z
= W'XY+XZ+Y'Z+W'Z
and im stucked. lol or i shouldnt approach it like this?

Answer 3

should i take out the z from the last 3 terms?