4.Solve 4x2 = 12x + 40. (1 point) typo this is the equation for #4
OpenStudy (anonymous):
sorry
OpenStudy (anonymous):
ok 8-40=2x
-32=2x
-32/2=x
x=-16
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OpenStudy (anonymous):
if is correct tell me
OpenStudy (anonymous):
4x^2=12x+40
4x^2-12x-40=0
let f(x)=4x^2-12x-40 (function)
Replace the value of x in such a way to obtain zero
f(-2)=0
(x+2) is a factor of f(x)
4x^2-12x-40=(x+2)(4x-20)=0
Either x=-2 or (4x-20=0>> x=5)