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Finds the value(s) of c if...
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\[\frac{a+b}{b+c}=\frac{c+d}{d+a}\]
\[\frac{-b-d \pm \sqrt{b^2+2bd+d^2+4a^2+4ad+4ab}}{2}\]
tricky c = a cross multiply a + b = b + c a = c
the answer is 5, or -5-b-d, but i have no idea how to get there
weird they they could come up wth a value like 5 if no numercal values provided by others?
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i have no idea either, i'm guessing it's a mistake because c could equal any number
How does c = a?
cross multiplied and assume that one side equal other side
I put it in Wolfram and they solved it by completing the square and got the same thing I got by using the quadratic formula.
im pretty sure you did good - note his answer is 5. Good Job.
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