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If f is one-to-one and f(4)=8, then f(4)^-1 is
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1/8?
Do you mean f(8)^-1?
... but that doesn't have anything to do with it being 1-to-1.
Like Mertsj said, do you mean f-inverse of 8?
1/8 works thanks
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So it was exponent -1 not f inverse.
yea
Who knew
i thought i wrote it well. you couldnt tell?
you did, indeed. hence leading off with 1/8 ... followed by the question mark :)
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ok thanks rulnick. im sorry if i confused you mertsj
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