Question

MEDALS ALL AROUND...

Hey guys, need some steps and some help on how to solve this:

(2x-3)/4 + (x-1)/3 =2

Answer 1

(2x-3)/4 + (x-1)/3 = 2
[3(2x-3) + 4(x-1)]/12 = 2
(6x - 9 + 4x - 4) = 2 * 12
10x - 13 = 24
10x = 37
x = 37/10 = 3.7

Hopefully that helps.

Answer 2

multiply each term by 12 common denominator

3(3x -3) + 4(x -1) = 24

expand

3x - 9 + 4x - 3 = 24

collect like terms

7x - 12 = 24

I'll let you solve it from here

Answer 3

oops 7x - 13 = 24