Question

y'=y-x

Answer 1

y=c e^x + x + 1

Answer 2

please show work

Answer 3

y' -y = -x
find integrating factor
e^-x

(e^-x)y' -(e^-x)y = -x(e^-x)
(ye^-x)' = -x(e^-x)

integrate both sides
y(e^-x) = e^-x(x+1) +C
y = x+1 +Ce^-x

Answer 4

typo...last part should be Ce^x