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integrate ((x+1)/(x^2+2x))dx
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Partial fractions: \[\frac{x+1}{x(x+2)}=\frac{A}{x}+\frac{B}{x+2} \implies Ax+2A+Bx=x+1 \implies A=\frac{1}{2}, B=\frac{1}{2}\] \[\int\limits \frac{x+1}{x^2+2x}dx=\frac{1}{2} \int\limits \frac{dx}{x}+\frac{1}{2} \int\limits \frac{dx}{x+2}=\frac{1}{2}\ln|x|+\frac{1}{2}\ln|x+2|+C\] \[=\ln|\sqrt{x}*\sqrt{x+2}|+C=\ln|\sqrt{x^2+2x}|+C\]
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