a rectangle has a length of 6x^3 y^2 - 1 and a width of 3xy+2.The formaula for the perimeter of a rectangle is P=2l+2w ,where l is length and w is the width.What is the perimeter of the rectangle?Simplify your answer.

Question

hero · Answer

http://openstudy.com/users/bimbim2697#/updates/4f53fbaee4b01ed6138314b3

hero · Answer

P = 2l + 2w
P = 2(l + w)
P = 2(6x^3y^2 - 1 + 3xy + 2)
P = 12x^3y^2 - 2 + 6xy + 4
P = 12x^3y^2 + 6xy + 2
P = 2(x^3y^2 + 3xy + 1)

anonymous · Answer

P=2 ( l+  w )
=  2 [ (6x^3 y^2 - 1 ) + (3xy+2)]
=  2 ( 6x^3 y^2 + 3xy + 1)

anonymous · Answer

There's nothing to simplify or calculate !

hero · Answer

I hate when I still make a mistake regardless of posting solution first.

hero · Answer

P = 2l + 2w
P = 2(l + w)
P = 2(6x^3y^2 - 1 + 3xy + 2)
P = 12x^3y^2 - 2 + 6xy + 4
P = 12x^3y^2 + 6xy + 2
P = 2(6x^3y^2 + 3xy + 1)