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integrate from 0 to 2 (squareroot of (6x+4)-2x
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\[\int\limits_0^2 \sqrt{6x+4}dx -2 \int\limits_0^2 x dx\] Let \[\xi=6x+4 \implies d \xi=6 dx \implies dx=\frac{d \xi}{6}\] \[\frac{1}{6} \int\limits_4^{16}\sqrt{\xi}d \xi-2 \int\limits_0^2 x dx\]
ty!
wait im kinda confused uhm wat i did was
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