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Mathematics 23 Online
OpenStudy (anonymous):

solve w^2+2w-96=0

sam (.sam.):

w^(2)+2w-96=0 w=(-b+-sqrt(b^(2)-4ac))/(2a) where aw^(2)+bw+c=0 w=(-2+-sqrt((2)^(2)-4(1)(-96)))/(2(1)) w=(-2+-2sqrt(97))/(2(1)) w=(-2+-2sqrt(97))/(2) ------------------------- w=-1+sqrt(97) w=-1-sqrt(97)

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