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OpenStudy (beth12345):
how to calculate for x when sin90/130=sinX/120
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OpenStudy (anonymous):
Cross multiply and then use the inverse sine.
OpenStudy (beth12345):
what is the inverse sine? is it \[\sin^{-1} \] ?
OpenStudy (anonymous):
To be more specific, 120sin90=130sinx x=sin^-1(120sin90/130)
OpenStudy (anonymous):
yes
OpenStudy (beth12345):
oh ok thanks
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