Let R be the region in the first quadrant enclosed by the graph of y=(6x+4)^(1/2), the line y=2x, and the y-axis.
(a)Find the area of R
(b)Set up, but do not integrate, an integral expression in terms of a single variable for the volume of the solid generated when R is revolved about the x-axis.
(c) Set up, but do not integrate, an integral expression in terms of a single variable for the volume of the solid generated when R is revolved about the y-axis.

anyone know the answer?

Question

Let R be the region in the first quadrant enclosed by the graph of y=(6x+4)^(1/2), the line y=2x, and the y-axis.
(a)Find the area of R
(b)Set up, but do not integrate, an integral expression in terms of a single variable for the volume of the solid generated when R is revolved about the x-axis.
(c) Set up, but do not integrate, an integral expression in terms of a single variable for the volume of the solid generated when R is revolved about the y-axis.


anyone know the answer?

anonymous · Answer

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